Hexagonal Prism Volume Calculator
Enter the side length and height of a regular hexagonal prism for its volume and surface area, drawn to scale. Click a dimension on the drawing to change it.
Dimensions
Hexagonal PrismResult
Volume of a hexagonal prism
A hexagonal prism has two regular six-sided ends joined by six rectangles. Its volume is the hexagon's area, (3√3⁄2)a², times the height. The surface adds the two ends to the six sides.
Editing on the drawing
Click the side length or the height on the figure, type a new value and press Enter to redraw the prism to scale.
How to find the volume of a hexagonal prism
A hexagonal prism has two regular six-sided ends connected by six rectangles — the shape of a pencil, a nut or a paver. Two measurements set a regular one: the side length of the hexagon and the height of the prism.
The formulas
The volume is the hexagon's area times the height. A regular hexagon of side a has area (3√3⁄2)a² — six equilateral triangles. The surface adds the two hexagonal ends to the six rectangular sides.
Worked example
Take a hexagonal prism with side 40 and height 84.
Area of a regular hexagon.
Base area times height.
Two ends plus six rectangles.
What else the calculator returns
You also get the base area, the lateral area, and the two key widths: across flats (√3·a, between opposite sides) and across corners (2a, between opposite vertices).
Where it comes up
Hexagonal-prism volumes describe bolts and nuts, pencils, paving and tiling, structural sections and honeycomb.
Frequently asked questions
How do you find the volume of a hexagonal prism?
Multiply the hexagon's area, (3√3⁄2)a², by the height h.
What is the area of a regular hexagon?
For side length a it is (3√3⁄2)a², the same as six equilateral triangles of side a.
What is the difference between across flats and across corners?
Across flats is the distance between opposite sides, √3·a; across corners is between opposite vertices, 2a. Spanner and bolt sizes quote across flats.
How do I find the height from the volume?
Divide the volume by the base area: h = V / ((3√3⁄2)a²).
Does this assume a regular hexagon?
Yes — all six sides equal and all angles 120°. An irregular hexagon needs its own measured cross-section area.